Find the value of k for which the lines 2x + 3y - 4 = 0 and kx + 6y + 5 = 0 are parallel.
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here two line are parallel therefore m1m2=0
a1a2+b1b2+c1c2=0
(2)(k)+(3)(6)+(-4)(5)=0
2k+18-20=0
2k=2
k=1
a1a2+b1b2+c1c2=0
(2)(k)+(3)(6)+(-4)(5)=0
2k+18-20=0
2k=2
k=1
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