Question

Find the value of k for which the lines (k + 1)x + 3ky + 15 = 0 and 5x + ky + 5 = 0 are coincident.

Answer 1

k=14
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Answer 2

Answer:

k=14

Step-by-step explanation:

The given equations are:

$(k+1)x+3ky+15=0$, and

$5x+ky+5=0$

Since, the given equations are coincident, therefore

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$

$\frac{k+1}{5}=\frac{3k}{k}=\frac{15}{5}$

Taking the first two terms, we have

$k=14$