find the value of k for which the lines kx-5y+4=0 and 4x-2y+5=0
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Answer:
5x-5y+4=0
5y=kx+4
y =k÷2x+4÷5
slope of this line =M1=k÷5
5m-2y+5=0
2y=5x+5
y=5÷2x++5÷2
slope of this line=M2=5÷2
Explanation:
since the line are perpendicular
M1 ×M2 = -1
k÷5×5÷2= -1
K = -2
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