Find the value of k for which the one root of quadratic equation kx2-14+8=0 is 2
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1
2k - 6 = 2 2k = 8 k = 8 / 2 k = 4
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5
kx^2 - 14x = 8
let x = 2 (given)
k(2)^2 - 14 (2) + 8
4K - 28 + 8 = 0
-4k = - 28 + 8
-4k = - 20
k=20/4
K = 5
easy na!!!
thank u!!! ;)
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