Question

find the value of k for which the origin of the equation is real and equal x² + k ( 2x + k - 1 ) + 2 = 0​

Answer 1

Step-by-step explanation:

The given equation is

x²+k(2x+k-1)+2

=x²+2kx+k²-k+2

=x²+2kx+(k²-k+2)

the roots are real and equal when

(2k)²-4(k²-k+2)=0

=> 4k²-4k²+k-2=0

=> k-2=0

=> k=2.

so the value of k is 2.

hope you got it.