Question

find the value of k for which the pair of equation 2x+ky+3=0,4x+6y-5=0 represent parallel lines
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Answer 1

Step-by-step explanation:

Compare the equation

2x+ky+3 and 4x+6y-5

a1=2

b1=k

c1=3

a2=4

b2=6

c2=-5

a1/a2=b1/b2 is not = to c1/c2

[Since the lines are parallel]

a1 /a2=b1/b2

2/4=k/6

[Cross multiplication]

2(6)=k(4)

12=4k

12/4=k

K=3

Therefore k value is 3