Question

find the value of k for which the pair of equations 2x-ky+3=0,4x+6y-5=0 represent parallel lines

Answer 1

2/4=-k/6
on solving k=-3
Hope it may help u

Answer 2

4x+6y-5=0
put it in the form of Y=mx+c
-6y= 4 x - 5
Y = - 4x/6 -5x/6
hence the slope= m1= -4/6


2x-ky+3=0

do the same thing as above.
therefore =
y= 2x/k + 3/k
hence the slope= m2= 2/k

parallel lines are mentioned so the slope of one line we be the same as the slope of the second line.
m1=m2
equate both the slopes
-4/6 = 2/k
after cross multiplying we get,
-4k = 12
therefore,
k= -3
Thank you:)