Question

find the value of k for which the pair of equations has a unique solution kx+2y=3,3x+6y=10​

Answer 1

Answer:k not equal to1

Step-by-step explanation:

since they have unique solution a1/a2 not equal to b1/b2

Answer 2

Answer:

Hence, The values of k is given by : { k : k ∈ R , k ≠ 1}

Step-by-step explanation:

The two pair of equations are given to be :

kx + 2y = 3 and 3x + 6y = 10​

$a_1=k,b_1=2\text{ and }a_2=3,b_2=6$

Now, we need to find the value of k such that the two pair of equations has a unique solution

The two equations have unique solution when the line of these equations intersect each other.

$\frac{a_1}{a_2}\neq\frac{b_1}{b_2}\\\\\implies \frac{k}{3}\neq\frac{2}{6}\\\\ \implies k\neq 1$

Hence, The values of k is given by : { k : k ∈ R , k ≠ 1}