find the value of k for which the pair of linear equation kx + Y is equal to K square and X + K Y is equal to 1 of infinity many solutions
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k i s = 1.
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kx + y = k^2
x + ky = 1
infinitely solution are possible if and only if:
k/1 = 1/k=k^2/1
by solving and equating these three fractions we get:
k^2= 1 and k^3 = 1
which is from both k = 1.
.....................................................................................
kx + y = k^2
x + ky = 1
infinitely solution are possible if and only if:
k/1 = 1/k=k^2/1
by solving and equating these three fractions we get:
k^2= 1 and k^3 = 1
which is from both k = 1.
rahul1222:
what
solve full plse
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2
Ans. K = 1
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