find the value of k for which the pair of linear equation kx +3y= k-3 and 12x+ky =k have no solution
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Answered by
2
k/12=3/k
k^2=36
k =6 and -6
k^2=36
k =6 and -6
Answered by
6
given
kx+3y=k-3
12x+ky=k
no solution means it is parrell ......
a1/a2=b1/b2 notequal to c1/c2
k/12=3/k not equal to 3/k
k/4=1/k notequal to 3/k
so k=4.......
kx+3y=k-3
12x+ky=k
no solution means it is parrell ......
a1/a2=b1/b2 notequal to c1/c2
k/12=3/k not equal to 3/k
k/4=1/k notequal to 3/k
so k=4.......
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