Question

find the value of k for which the pair of linear equation x+2y_5=0 and 3x+6y+k=0 ​

Answer 1

Answer:

k=15

Step-by-step explanation:

x+2y-5=0

x=5-2y

3x+6y+k=0

3(5-2y)+6y+k=0

15-6y+6y+k=0

k=-15

Answer 2

The value of k is equal to - 15.

Step-by-step explanation:

The given pair of linear equations are:

x + 2y - 5 = 0              ......... (1)

and

3x + 6y + k = 0         ......... (2)

To find, the value of k = ?

Multiplying equation (1) by 3, we get

3(x + 2y - 5) = 3(0)            

3x + 6y - 15 = 0           ......... (3)

Subtracting equation (2) from (3), we get

3x + 6y + k - (3x + 6y - 15)= 0 - 0    

⇒ 3x + 6y + k - 3x - 6y + 15 = 0

⇒ k + 15 = 0

⇒ k = - 15

Thus, the value of k is equal to - 15.