find the value of k for which the pair of linear equation x+2y_5=0 and 3x+6y+k=0
Answers
Answered by
4
Answer:
k=15
Step-by-step explanation:
x+2y-5=0
x=5-2y
3x+6y+k=0
3(5-2y)+6y+k=0
15-6y+6y+k=0
k=-15
Answered by
2
The value of k is equal to - 15.
Step-by-step explanation:
The given pair of linear equations are:
x + 2y - 5 = 0 ......... (1)
and
3x + 6y + k = 0 ......... (2)
To find, the value of k = ?
Multiplying equation (1) by 3, we get
3(x + 2y - 5) = 3(0)
3x + 6y - 15 = 0 ......... (3)
Subtracting equation (2) from (3), we get
3x + 6y + k - (3x + 6y - 15)= 0 - 0
⇒ 3x + 6y + k - 3x - 6y + 15 = 0
⇒ k + 15 = 0
⇒ k = - 15
Thus, the value of k is equal to - 15.
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