find the value of 'k'for which the pair of linear equation x+2y-5=0 and 3x+6y+k=0 represent coincident lines
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Answered by
5
Step-by-step explanation:
coincident lines
a1/a2 = b1/b2 = c1/c2
so
1/3=2/6=-5/k
1/3=-5/k
k=-15
Answered by
2
value of k = -15
we have to find out value of k for which the pair of linear equation x+2y-5=0 and 3x+6y+k=0 represent coincident lines.
applying condition,
a1/a2 = b1/b2 = c1/c2
where a1, b1, c1 are coefficient of x , y and constant of first equation. and a2, b2, c2 are of 2nd equation.
here, a1 = 1, b1 = 2, c1 = -5
a2 = 3, b2 = 6 , c2 = k
now, 1/3 = 2/6 = -5/k
⇒1/3 = -5/k
⇒k = -15
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find the value of 'k'for which the pair of linear equation x+2y-5=0 and 3x+6y+k=0 represent coincident lines
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