Math, asked by abedisyeda9940, 11 months ago

find the value of 'k'for which the pair of linear equation x+2y-5=0 and 3x+6y+k=0 represent coincident lines​

Answers

Answered by santhosh72586
5

Step-by-step explanation:

coincident lines

a1/a2 = b1/b2 = c1/c2

so

1/3=2/6=-5/k

1/3=-5/k

k=-15

Answered by abhi178
2

value of k = -15

we have to find out value of k for which the pair of linear equation x+2y-5=0 and 3x+6y+k=0 represent coincident lines.

applying condition,

a1/a2 = b1/b2 = c1/c2

where a1, b1, c1 are coefficient of x , y and constant of first equation. and a2, b2, c2 are of 2nd equation.

here, a1 = 1, b1 = 2, c1 = -5

a2 = 3, b2 = 6 , c2 = k

now, 1/3 = 2/6 = -5/k

⇒1/3 = -5/k

⇒k = -15

also read similar questions : Find the value of k for which pair of equations 2x-KY+3=0 and 4x+6y-5=0 represent parallel lines

https://brainly.in/question/7625479

find the value of 'k'for which the pair of linear equation x+2y-5=0 and 3x+6y+k=0 represent coincident lines

Similar questions