Question

find the value of k for which the pair of linear equationa 2x+3y=7 and (k-1)x +(k+2)y=3k have infinitely many solutions​

Answer 1

Answer:

k=7

Step-by-step explanation:

Let the equation (i) be 2x + 3y – 7 = 0  

Let the equation (ii) be (k – 1)x + (k + 2)y – 3k = 0  

We have,

For infinite number of solutions

2k–1=3k+2=−7−3k

2k–1=3k+2=73k

Now, the following cases arises

Case 1:

2k–1=3k+2

2(k+2)=3(k–1)⇒2k+4=3k−3

k=7

Case 2:

3k+2=73k

(k+2)=9k⇒7k+14=9k

k=7

Case 3:

2k–1=73k

7k–7=6k

k=7

Read more on Brainly.in - https://brainly.in/question/2166540#readmore

Answer 2

Answer:

k=-5/7

Step-by-step explanation:

this is the explanation