find the value of k for which the pair of linear equations (3k+1)x +5y -2= 0 and (k²+1)x + (k-2)y -5=0 have no solution
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the value of k will be find through a1/a2=b1/b2 is not equal to c1/c2
3k+1/k^2+1=5/k-2 and 5/k-2 is not equal to -2/-5
solve this two equations and find the value of k
hope this is help for you
3k+1/k^2+1=5/k-2 and 5/k-2 is not equal to -2/-5
solve this two equations and find the value of k
hope this is help for you
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