Question

Find the value of k for which the pair of linear equations kx+2y=3 ,3x+6y=10
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Answer 1

Answer:

The value of k = -1 / 3x + 1 or (-1 + 3x) / 3x

Step-by-step explanation:

From equation 3x + 6y = 10, we will find y

y = 10 - 3x / 6

Putting the value of y in equation kx + 2y = 3

kx + 2 (10 - 3x / 6) = 3

kx + 10 - 3x / 3 = 3

3 kx + 10 - 3x = 9

3 kx - 3x = 9 - 10

3x (k - 1 ) = -1

k - 1 = -1 / 3x

k = -1 / 3x + 1 or (-1 + 3x) / 3x