find the value of k for which the pair of linear equations 3x+ky+2y=0,6x-8y+7=0 represent the parallel lines
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Answer:
Step-by-step explanation:
3x+(k+2)y=0.............................[1]
6x-8y+7=0..................................[2]
here
a1=3 , a2=6
b1=k+2, b2=-8
c1=0 , c2=7
condition for parallel lines
a1/a2 is equal to b1/b2 is not equal to c1/c2
a1/a2=3/6=1/2
b1/b2=k+2/-8
c1/c2=0/7=0
by condition
1/2=- k+2/8
-k-2=4
-k=6
k=-6
hope it helps
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