Question

find the value of k for which the pair of linear equations 4x+6y-1=0 and 2x+ky-7= 0 represent parallel lines​

Answer 1

Given ,

The pair of linear equations 4x + 6y - 1=0 and 2x + ky - 7= 0 represent parallel lines

As we know that ,

If two lines are parallel lines , then

$\boxed{ \tt \frac{ a_{1} }{ a_{2}} = \frac{ b_{1} }{ b_{2}} ≠ \frac{ c_{1} }{ c_{2}}}$

Thus ,

4/2 = 6/k

4k = 12

k = 12/4

k = 3

$\therefore$ The value of k is 3