Math, asked by chanchiyaveena, 8 months ago

Find the value of k for which the pair of linear equations 5x-3y=0,4x+ky=0 has a non zero solution.
Class 10.
Chapter name:- Pair of linear equations in two variables.
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Answers

Answered by laveshgupta76
1

Answer:

answer is k=12/5

Step-by-step explanation:

we know  that non zero solution will be infinte many solution

so,  a{1}/ a{2}=b_{1}/b_{2}=c_{1} /c_{2}

5/4=3/k

5(k)=4(3)

5k=12

k=12/5

Answered by Anonymous
8

Given :-

  •  \tt \: 5x-3y=0 \\ </li><li></li><li> \tt4x+ky=0

To Find :-

  •  \tt \: The \:  value  \: of \:  \red k.

Solution :-

 \mapsto \tt\: 5x-3y=0 \\ </p><p></p><p> \mapsto \tt4x+ky=0

 \tt \: Here,

  \mapsto\tt \: a_1 = 5, \: b_1 =  - 3,  \: c_1 = 0</p><p></p><p></p><p></p><p></p><p>

 \mapsto \: \tt \: a_2= 4, \: b_2=  k,  \: c_2= 0

 \tt \: Now,

{\tt{ \boxed{ \tt{ \frac{a_1}{a_2 }  =  \frac{b_1}{b_2} }}}}

 \tt \: putting \: values \:

 \tt \mapsto \:  \frac{5}{4}  =  \frac{ - 3}{k}

\tt \mapsto \:5k =  - 12

\tt \mapsto \:k =  \frac{ - 12}{5}

 \huge\tt \:{ \boxed{ \tt{ \blue{k =  - 2.4}}}}

Hence,

  • The value of k is -2.4 .
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