Question

Find the value of k for which the pair of linear equations kx + 3y=k-2 and 12x+ky=k

Answer 1

kx+3y=k-3 ---(1)

12x+ky=k ---(2)

Here, a1=k b1=3 c1= -(k-3)

a2= 12 b2=k c2= -k

Now, a1/a2=b1/b2≠c1/c2

=> a1/a2= b1/b2

=> k/12= 3/k

=> k2= 36

=> k=6

Now, putting value of k=6, the solution automatically satisfy condition i.e.

a1/a2=b1/b2≠c1/c2

SO value of k is 6.

Hope it helps!