Find the value of k for which the pair of linear equations kx+3y=k-2 and 12x+ky=k has no solutions
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There is no solution therefore,
A1/A2=B1/B2 is not equal toC1/C2
A1=K;A2=12;B1=3;B2=K
SO, K/12=3/K
K^2=36 (cross-multiplication)
Therefore,K =6 (square root of 36 is 6)
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