Question

find the value of k for which the point (0,2) is equidistant from (3,k) and (k,5)

Answer 1

Step-by-step explanation:

given P (0,2) is equidistant from R (3,k) ans S (k,5)

therefore, PR=PS

=> PR²=PS²

=> (3-0)²+(k-2)²=(k-0)²+(5-2)². [using distance formula ]

9+k²+4-4k =k²+9

4=4k

k=4/4

k=1 ans

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