Question

find the value of k for which the point (1,2) lies on the graph of the linear equation x-2y+k=0​

Answer 1

Answer:

so friends when we need to find the value of k so

Step-by-step explanation:

x-2y+k=0

let x=1 and y=2 than solve

1-2(2)+k=0

1-4+k=0

-3+k=0

k=3

Answer 2

The value of k is 3.

Step-by-step explanation:

Given : The point (1,2) lies on the graph of the linear equation $x-2y+k=0$

To find : The value of k ?

Solution :

If the point (1,2) lies on the linear equation $x-2y+k=0$ it will satisfy the equation.

$x-2y+k=0$

$1-2(2)+k=0$

$1-4+k=0$

$-3+k=0$

$k=3$

Therefore, the value of k is 3.

#Learn more

Find the value of k if the graph of the equation 3x+ky=5 passes through the point (-1,2) . For what value of k will the graph pass through (1,0) ?

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