Question

Find the value of k for which the point (1,-2) lies on the graph of the linear equation x-2y+k=0.

Answer 1

Step-by-step explanation:

let's take

x=1 and y= -2

now p(x,y)=x-2y+k=0

substitute x and y values in this equation

=p(1,-2)=(1)-2(-2)+k=0

=4+k=0

=k=-4

here is your answer

Answer 2

Answer:

x-2y+k=0

we have,

x=1

y= -2

therefore,

1-2(-2)+k=0

1+4+k=0

5+k=0

k= -5

Step-by-step explanation:

we have points of x-axis and y-axis

substitute values of x and y solve equation as solved above hence we can find the value of k