Math, asked by kimaya5162, 9 months ago

Find the value of k for which the point(1,-2) lies on the graph of the linear equations x-2y+k=0

Answers

Answered by tsradhanjali3

2

Answer:

k=-5

Step-by-step explanation:

Given equation of line is x-2y+k=0

Given the point is (1,-2)

1-(-2)+k=0

5+k=0

k=-5

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