Math, asked by mohammedyahirsheikh, 7 months ago

find the value of k for which the point (1 -2) lies on the graph of the linear equation x-2y+k=0

Answers

Answered by rajunaga110

4

Answer:

-5

Step-by-step explanation:

if given points are lie the linear equation then

1-2(-2)+k=0

1+4+k =0

5+k =0

k=-5

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