- Find the value of “k” for which the point (1 ,-2) lies on the graph of linear equation x - 2y + k = 0. Hence find one more solution of the given
equation.
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2
Answer:
-5
Step-by-step explanation:
x=1,y=-2
1-2(-2)+k=0
1+4+k=0
5+k=0
k=-5
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