find the value of k for which the point (-1 , 3)lies on the graph of the equation 2 x minus y + k = 0
Answers
Answered by
1
it is given that,the point lies on the line 2x-y+k=0,
therefore,it must satisfy the line equation.
substituiting (-1,3) in the equation,we get,
2(-1)-(3)+k=0
=> -2-3+k=0
or k=5.
therefore,it must satisfy the line equation.
substituiting (-1,3) in the equation,we get,
2(-1)-(3)+k=0
=> -2-3+k=0
or k=5.
Similar questions