find the value of k for which the point A - 1, 3 B 2, K and C 5 - 1 are collinear
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1
Answer:
Step-by-step explanation:
Given A(-1,3) B(2,k) C(5,-1)
-1 3
2 k
5 -1
-1 3
(-k+2+15)-(6+5k+1)
(-k+17)-(5k+7)
(-k+17)=(-5k-7)
-k+5k=17+7
4k=24
K=24/4
K=6
gautamsimran:
Okkk
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0
Please take P as K to get the answer
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