find the value of k for which the points (7,2) (5,1) (3,k) are collinear
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Step-by-step explanation:
Point A(7,−2),B(5,1) and C(3,k) are collinear if
Slope of AB= Slope of BC
5−7
1−(−2)
=
3−5
k−1
−2
3
=
−2
k−1
⇒k−1=3
k=3+1=4
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