Question

find the value of k for which the points(7,-2) (5,1) (3,k) are collinear.

Answer 1

Answer:

K=4

Step-by-step explanation: in the attachment⬇⬇

Hope it helps you✌✌

Answer 2

Answer:

Step-by-step explanation:

1/2 |x1(y2-y3)+x2(y3-y1)+x3(y1-y2)| = 0

1/2|7(1-k)+5(k+2)+3(-2-1)| = 0

7-7k+5k+10-9=0

8-2k=0

K= -8/-2

K=4