find the value of k for which the points (7 -2) (5 ,10) (3 k)
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If the points are nonlinear then the area of triangle will be 0.
= 1/2 | x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2 ) |
= | 7 ( 1 - k) + 5 ( k + 2 ) + 3 (- 2 -1 ) | = 0
= | 7-7k + 5k + 10 - 9 | =0
= | - 2k + 8 | = 0
= - 2k = - 8,so
k = 4
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