Question

find the value of K for which the points A(1,2), B (-1,k), C (-3,-4) are collinear.​

Answer 1

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Answer 2

Answer:

k=-1

Step-by-step explanation:

there are many methods to solve this but most preferable process is area of triangle formula's process

1/2|X1(y2-y3)+X2(y3-y1)+x3(y1-y2)|=0

it's zero because points are collinear

1/2|1(k-(-4)-(1)((-4)-2)+(-3)(2-k)|=0

1/2|k+4+6-6+3k|=0

1/2|4k+4|=0

4k+4=0

4k=-4

k=-1