find the value of k for which the points are collinear(7,-2)(5,3)(3,k)
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Answer:
Step-by-step explanation:
If the points are collinear then the area of triangle will be O.
Δ= 1/2 ∣ x 1 ( y 2 − y 3 ) + x 2 ( y 3 − y 1 ) + x 3 ( y 1 − y 2 ) ∣
1 / 2 ∣ 7 ( 3 − k ) + 5 ( k + 2 ) + 3 ( −2 −3 ) ∣ = 0
∣ 21 − 7k + 5k + 10 − 15 ∣ = 0
∣ −2k - 16 ∣ = 0
-2k = 16
so k = -8
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