Math, asked by Sammer1971, 1 year ago

find the value of K for which the points are collinear (7,-2) (5,1) (3,K)

Answers

Answered by kumarankur164p7u2qy
1
here is ur answer hope you like it
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Answered by STR9
1

(1 - ( - 2)) \div (5 - 7) = (k - 1) \div (3 - 5)
 - 3 \div 2 = (k - 1) \div  ( - 2)
3 = (k - 1) \\ k = 4

STR9: (y2-y1)/(x2-x1)=(y3-y2)/(x3-x2)=(y3-y1)/(x3-x1)
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