Question

Find the value of k for which the points with coordinates (2,5)(k,11/8) and (4, 6) are collinear​

Answer 1

Answer:

Step-by-step explanation

Let the given points be

A(2,5) ,B(k,11/8) and C(4,6)

Let us consider that ABC is a triangle

then ar(ABC)=0

1/2{2(11/8-6)+k(6-5)+4(5-11/8)}=0

1/2{2(-37/8)+k(1)+4(29/8)}=0

1/2{-37/4+k+29/2}=0

-37/4+29/2+k=0

k=37/4-29/2

k=-21/4