Question

Find the value of k, for which the polynomial 2x³+3x²+3x–k has 2 as its zero .

Answer 1

put x=2

$2 \times {2}^{3} + 3 \times {2}^{2} + 3 \times 2 - k = 0$

$= 16 + 12 + 6 - k = 0$

$= k = 34$

Answer 2

Answer:

2x³+3x²+3x–k has 2 as its zero

so p(x) = 0

p(x) = 2x³+3x²+3x–k

p(2) = 2x³+3x²+3x–k

p(2) = 2(2)³+3(2)²+3(2)–k

p(2) = 16 + 12 + 6 - k

0 = 34 - k

k= 34 Answer.....