Question

Find the value of k for which the polynomial kx3
+ 9x2
+ 4x – 10 leaves the
remainder -22 when divided by (x-1)

Answer 1

hii your answer is there in the attachment

Answer 2

Step-by-step explanation:

p(x)= (x-1)(kx² + (9-3k)x - 23 + 9k) = 61-27k

now remainder equals = -22

so 61-27k = -22

⇒ 81 = 27k

hence k = 3