find the value of k for which the polynomial x²+5x²+4
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Answer:
The given quadratic equation is ;
(k-5)x² + 2(k-5)x + 2 = 0
Clearly , we have ;
a = k-5
b = 2(k-5)
c = 2
We know that ,
The quadratic equation will have equal roots if its discriminant is equal to zero .
=> D = 0
=> [2(k-5)]² - 4•(x-5)•2 = 0
=> 4(k-5)² - 4•2(k-5) = 0
=> 4(k-5)•(k-5-2) = 0
=> (k-5)(k-7) = 0
=> k = 5 , 7
Hence,
The required values of k are 5 and 7
Step-by-step explanation:
hope u have been understood
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