Question

find the value of k for which the polynomial x²+5x²+4​

Answer 1

Answer:

The given quadratic equation is ;

(k-5)x² + 2(k-5)x + 2 = 0

Clearly , we have ;

a = k-5

b = 2(k-5)

c = 2

We know that ,

The quadratic equation will have equal roots if its discriminant is equal to zero .

=> D = 0

=> [2(k-5)]² - 4•(x-5)•2 = 0

=> 4(k-5)² - 4•2(k-5) = 0

=> 4(k-5)•(k-5-2) = 0

=> (k-5)(k-7) = 0

=> k = 5 , 7

Hence,

The required values of k are 5 and 7

Step-by-step explanation:

hope u have been understood