Question

Find the value of k for which the polynomial x3-4x2+2x+k has 3as its zero.

Answer 1

$let \: f(x) = {x}^{3} - 4 {x}^{2} + 2x + k$
given that 3 is a zero of f(x)
so,f(3)=0
substitute x=3 in the given polynomial
=>
${(3)}^{3} - 4 {(3)}^{2} + 2(3) + k = 0$
$= > 27 - 36 + 6 + k = 0$
=>k=36-6-27
=>k=36-33
=>k=3
.
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Answer 2

Answer:

answer is in attachment hope it will help you please mark me brainlist