Question

find the value of k for which the polynomial x⁴+10x³+25x²+15x+k is exactly divisible by x+7

answee= -89 ana chahiye ​

Answer 1

Answer:

k=-3178

Step-by-step explanation:

Remainder Theorem:-

x+7=0

x=-7

Now substitute x=-7 in $x^{4}$+$10x^{3}$+$25x^{2}$+$15x^{}$+k=0

$(-7)^{4}$+$10(-7)^{3}$+$25(-7)^{2}$+$15(-7)^{}$+k=0

2401+(-343)+1225+(-105)+k=0

2401-343+1225-105+k=0

3626-448+k=0

3178+k=0

k=-3178

Answer 2

Refers to attachment ┈━═☆

hope IT HELPs

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