Find the value of k for which the quadralic equation 2x²-kx+3=0 has two equal roots
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Answer:
Find the values of k for quadratic equation 2x2 + kx + 3 = 0, so that they have two equal roots.
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Step-by-step explanation:
given,
2x^2+Kx+3
here it is in the form ax^2+bc+C=0
here a=2, b=K, c=3
if it has two equal roots. then A=0
b^2-4ac=0
k^2-4(2)(3)=0
k^2-24=0
k^2=24
k=√24
k=2√6
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