Find the value of k for which the quadratic equation 2x^2+kx+2=0 has equal roots
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Step-by-step explanation:
Compare given Quadratic equation 2x²-kx+k=0 with ax²+bx+c=0, we get
a = 2,b = -k , c = k,
Discreminant (D)=0
[ Given roots are equal ]
=> b²-4ac=0
=> (-k)²-4×2×k=0
=> k²-8k=0
=> k(k-8)=0
=> k = 0 or k=8
Therefore the value ok k = 0 or 8
.
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