find the value of k for which the quadratic equation 2x^2-kx +k=0 has equal roots
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HEY BUDDY HERE IS UR ANSWER !!!
2x^2-kx +k=0
a = 2
b= -k
c= k
D = b^2 - 4 ac = 0
D = (-k)^2 - 4 (2)(k) = 0
D = k^2 - 8k = 0
K = 8
2x^2-kx +k=0
a = 2
b= -k
c= k
D = b^2 - 4 ac = 0
D = (-k)^2 - 4 (2)(k) = 0
D = k^2 - 8k = 0
K = 8
Sweetbuddy:
Thanks !!! ^___^
if u wouldn't get trouble would you like do one more sum for me
yeah sure
Find the 7th term of the sequence whose nth term is given by an=(-1)^n-1.n^3
i posted it already before 6minutes
ok
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