Find the value of k for which the quadratic equation 2x²+ 5x + k =0 has no real roots.
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Answered by
2
The Following Equation has Real Roots
Hence , Delta = 0 or Delta > 0
Now The Equation
2x² + 5x + k = 0
Now By comparing the equation with ax² + bx + c = 0
We get
a = 2 , b = 5 , c = k
Now ∆ = Delta = b² - 4ac = 0
....According to the question
5² - 4 ( 2) ( k) = 0
25 - 8k = 0
25 = 8k
k = 25/8
Hence the value of K will be 25/ 8
Hence , Delta = 0 or Delta > 0
Now The Equation
2x² + 5x + k = 0
Now By comparing the equation with ax² + bx + c = 0
We get
a = 2 , b = 5 , c = k
Now ∆ = Delta = b² - 4ac = 0
....According to the question
5² - 4 ( 2) ( k) = 0
25 - 8k = 0
25 = 8k
k = 25/8
Hence the value of K will be 25/ 8
Answered by
0
given equation; 2x² + 5x + k = 0
for no real root
D< 0
D = b -4ac
b²-4ac is less than zero the roots are not real.
a=2, b=5, c = k
b²-4ac<0
25-4(2)k <0
25-8k <0
-8k < -25
k>25/8
k>3.125
hope so correct and helpful !!!!!!!!!!!!!!!!!!!!!!!
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