find the value of k for which the quadratic equation 2x2+8x-k3=0 has two equal roots
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8
Answer:
=> k = + 2 √2
Step-by-step explanation:
roots of a quadratic equation given by
x = -b + √ ( b^2-4ac) / 2a { quadratic formula }
if this has equal roots then discriminent D must equal to 0
so that , x = -b + 0 / 2a = -b/2a
here b = 8
a = 2
c = k^3
=> (8) ^2 - 4×2 ×k^3 = 0
=> 8( 8 - k^3 ) = 0
=> k^3 = 8
=> k = + (8)^ 1/3
=> k = + 2 √2
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