Find the value of K for which the quadratic equation 2x²+kx+3=0 has two real equal roots.
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Refer to the above attachment ⬆️
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Step-by-step explanation:
2x² + kx + 3 = 0
d = b² - 4ac = 0
Compare these equations
ax² + bx + c = 0
a = 2 , b = k , c = 3
D = k² - 4×2×3 = 0
D = k² - 24 = 0
K = √24
K = ± 2√6
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