Question

Find the value of k for which the quadratic equation
2x2 + kx + 3 = 0 has two real equal roots.. plzzzzz do it fast​

Answer 1

Answer:

2√6

Step-by-step explanation:

For an equation in form of ax² + bx + c = 0(a≠0) to have real and equal roots, must have 0 discriminant. Discriminant for this equation is b² - 4ac.

For 2x² + kx + 3 = 0.

=> b² - 4ac = 0

=> k² - 4(2)(3) = 0

=> k² = 24

=> k = 24 = 2√6

Answer 2

Answer:

Since equation has real roots

b^2-4ac=0

Substituting the values by comparing to standard equation

k^2-4(2)(3)=0

k^2-24=0

k=2√6

Hope it helps<3