Question

Find the value of k for which the quadratic equation: 2xsq + kx + 2 =0 has equal roots​

Answer 1

kindly see the answer below...

Step-by-step explanation:

As given here that the quadratic equation has equal roots.

then

$b {}^{2} - 4ac = 0$

therefore,

$f(x) = 2 {x}^{2} + kx + 2 = 0$

so,

$a = 2$

$b = k$

$and \: c = 2$

then, putting the value in the equation, we get

b²-4ac=0

or, k²-4×2×2=0

or, k²=16

or, k=±4...

thanks a lot...

Answer 2

Answer

K=+or - 4

Solve it using the formula b sq - 4ac