Math, asked by ingalebhupen9744, 1 year ago

Find the value of k for which the quadratic equation (3k+1)x^2+2(k+1)x+1=0 has equal root also find these roots.

Answers

Answered by raja7044
0


K=-1 is the answer to your question
Answered by KnowMore
1
ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ :-


( 3ᴋ + 1 )x² + 2 ( ᴋ + 1 ) + 1 = 0


ᴄᴏᴍᴘᴀʀɪɴɢ ᴛʜᴇ ᴇǫᴜᴀᴛɪᴏɴ ᴡɪᴛʜ sᴛᴀɴᴅᴀʀᴅ ғᴏʀᴍ


ʜᴇʀᴇ


ᴀ = 3ᴋ + 1


ʙ = 2( ᴋ + 1 )


ᴄ = 1


sɪɴᴄᴇ ᴛʜᴇ ɢɪᴠᴇɴ ǫᴜᴀᴅʀᴀᴛɪᴄ ᴇǫᴜᴀᴛɪᴏɴ ʜᴀs ᴇǫᴜᴀʟ ʀᴏᴏᴛs ᴛʜᴇ ᴅɪsᴄʀɪᴍɪɴᴀɴᴛ = 0


ʙ² - 4ᴀᴄ = 0


( 3ᴋ + 1 )² - 4 ×2( ᴋ + 1 )( 1 ) = 0


=> 9ᴋ² + 6ᴋ + 1 - 8ᴋ - 8 = 0


=> 9ᴋ² - 2ᴋ - 7 = 0


=> 9ᴋ² - 9ᴋ + 7ᴋ - 7 = 0


=> 9ᴋ ( ᴋ - 1 ) + 7 ( ᴋ - 1 ) = 0


=> ( ᴋ - 1 )( 9ᴋ + 7 ) = 0


=> ᴋ - 1 = 0. ᴏʀ. 9ᴋ + 7. = 0


=> ᴋ = 1 ᴏʀ. ᴋ = -7/9

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