Math, asked by neeladrisen2004, 6 months ago

find the value of k for which the quadratic equation 3x^2-5x+2k=0 has real and equal roots​

Answers

Answered by ankita900sharma
2

Answer:

given quadratic equation is

3x^2-5x+2k=0

Condition for equal roots:

b^2 -4ac=0         -----eq(1)

here comparing with the given equation

a=3,b=5,c=2k ,putting these values in eq (1)

5^2-4(3)(2k)=0

25-24k=0

25=24k

k=25/24

Step-by-step explanation:

Similar questions